Visitor

2016-06-21 18:53:30

#1

The measures of the angles A, B, C of a triangle ABC are inversely proportional to the numbers: 0, (3), 0.5, 0.25. A parallel to the side BC intersects the perpendicular from C to point D. Find out the measures angles in the quadrilateral ABCD.

Visitor

2016-06-21 19:01:01

#2

We have this image

And now this string of raports

, i.e.

and now it becomes

and find out the angles of the ABC triangle

m(A) = 60°

m(B) = 40°

m(C) = 80°

Now we have to do

**m(BAD) =** m(BAC) + m(CAD) = m(BAC) + m(ACB) = 60° + 80° = **140°**

m(CAD) = m(ACB) because they are two angles formed by two parallel lines cut by a secant.

And then, in the quadrilateral ABCD, we have**m(B) = 40°**

**m(BCD) = 90°**

**m(D) = 90°**

And now this string of raports

, i.e.

and now it becomes

and find out the angles of the ABC triangle

m(A) = 60°

m(B) = 40°

m(C) = 80°

Now we have to do

m(CAD) = m(ACB) because they are two angles formed by two parallel lines cut by a secant.

And then, in the quadrilateral ABCD, we have

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